H=73t-5t^2

Solution for H=73t-5t^2 equation:

=73H-5H^2

We move all terms to the left:

-(73H-5H^2)=0

We get rid of parentheses

5H^2-73H=0

a = 5; b = -73; c = 0;
Δ = b2-4ac
Δ = -732-4·5·0
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-73}{2*5}=\frac{0}{10}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+73}{2*5}=\frac{146}{10}
=14+3/5
$